(1/6)^(2n)=36^(-2n)

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Solution for (1/6)^(2n)=36^(-2n) equation: 



(1/6)^(2n)=36^(-2n)

We move all terms to the left:

(1/6)^(2n)-(36^(-2n))=0



Domain of the equation: 6)^2n!=0

n!=0/1

n!=0

n∈R



We add all the numbers together, and all the variables

(+1/6)^2n-(36^(-2n))=0

We multiply all the terms by the denominator


(+1-((36^(-2n)))*6)^2n=0

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